The magnitude of that, we'll just write it without the vector notation.
Vector right over here, we can write like this. Magnitude of the vector in the X direction, so this That the magnitude of A is 330 newtons, so the magnitude - let me just say that the magnitude - let me just write it this This right over here is a right triangle. The way we can do that is just with our traditional trig functions. So what we really want toĭo is find the component, the magnitude of the component going in that direction right over there. Is some place out here, we've already been told The magnitude of vector A is equal to 330 newtons, and if we say that the target is in thisĭirection right over here, so that's the target So vector A looks like this,Īnd I'll just draw them separately just so we canĬlean it up a little bit. In this direction, in the direction towards the target. Go more in that direction? And by how much more? And also, what's the total force now pushing the box in that direction? So I'm assuming you had a go at it, and the key here is to find the component of each of these vectors, the magnitude of each of these vectors 330 newtons versus 300, but who's helping the box We see that person A is exerting a total, a higher magnitude ofįorce in this direction than person B is doing in that direction. Of each of their force is going in the direction of getting the box towards the target, and then who is actually exerting moreįorce in that direction. Now what I want you toĭo, is pause this video and think about how much Of the target right over here we know that this is a 35 degree angle, and we know that this And we know their angles that those make with the direction of the target. Magnitude of that force, of that vector of personī's pushing, is 300 newtons. This angle right over here, so that right over there, that vector is the force that person B is pushing onto it and the direction, and the Soft right over here, person B is pushing at And let's say person B, once again, because they can't push exactly in the direction of the target, maybe the box is really So this is person A's force vector, and we know the length of this vector, or another way to thinkĪbout it, the magnitude of vector A is 330 newtons, 330 newtons. This vector I'm drawing, essentially represents theįorce that they're exerting. So person A has to push in a direction that's notĮxactly going in the direction of the target, so they push in a direction that looks like this, and so let me show you There, maybe the box squeezes a little bit, Some reason, they can't push it from exactly behind the box, maybe there's not a good footing there, or I guess if they pressed Trying to get the box, and person A, because for This is where the box is, right over here and this is
Push a box across the snow towards a target, so You have two folks that are trying to collectively
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